In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?

1 answer:

5 0

4sqrt(3)

See the diagram below.

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Kitty [74]

Answer:

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Degger [83]

Answer:

m = -3

Step-by-step explanation:

5m + 20 = 8 + 2m +3

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andreev551 [17]

The correct answer is B.

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Katarina [22]

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Step-by-step explanation:

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GenaCL600 [577]

Answer:

Step-by-step explanation

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