Answer:
x = 24 + y
Step-by-step explanation:
Move all terms that don't contain x to the right side and solve.
Part a.
<span>The perimeter formula is: </span>
P = 2w + 2LYour answer for part A is
P = 2w + 2LPart b.
They tell us in part b, that:
w = 6L + 20
Substitute that into what we got for part a.
P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40Your answer for partb is
P = 14L + 40Part c.
So we take what we got from part b, and solve for L.
P = 14L + 40
14L = P - 40
![L = \boxed{\frac{P-40}{14}}](https://tex.z-dn.net/?f=L%20%3D%20%5Cboxed%7B%5Cfrac%7BP-40%7D%7B14%7D%7D)
That is your answer for part 3 ^
part d.
Plug in w = 32 into what we first got in part b.
w = 6L + 20
32 = 6L + 20
6L = 12
L = 2Your answer for part d is
L = 2<span>:D</span>
(5 + 3) / (-2 -8) = 8/-10 = -4/5
Answer: Hello!
Lets segment our phrase:
The ______ class limit is the smallest value within the class.
The lower limit of a sequence, is a therm that is smaller than al the therms in the sequence, and does not belong in the sequence, for other part, the minumum refers to the smaller therm in the sequence, here you can see that the phrase is refering to "the smallest value within the class" so this number is in the set, then the correct answer is "minumum".
and the ______ class limit is the largest value within the class.
Here again, we are talking of values within the set (where the set is the class in this problem) then the correct answer in this case is "maximum".