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3 years ago

12

Find the volume of a sphere that has a surface area of 16 * pi sq. in.

1 answer:

Thepotemich [5.8K]3 years ago

4 0

You can use this formula to solve this problem... it uses the surface area to find the volume.

V= (A^3/2)/(6√pi)

Substitute the surface area value into "A" and then solve as you would on paper. I'm sorry I couldn't show you the entire process but this should get you your answer. Plus if your teacher asks for work, I just set you up and everything else should be self explanatory.

But the answer is ----> 33.5 inches cubed

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

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Juli2301 [7.4K]

Answer:

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.05 is equal to 5/100

.09 is equal to 9/100

.9 is equal to 9/10

Step-by-step explanation:

Hope this helps! Mark me and brainliest if it does!

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