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Brrunno [24]
3 years ago
10

HELP AGAIN!!!!!!!!

Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

90

Step-by-step explanation:

Partition the figure by extending the sides of the ``middle'' square as shown at the right. Each original square contains four $3 \times 3$ small squares. The shaded figure consists of ten $3 \times 3$ squares, so its area is $10 \times 9 = \boxed{90\text{ square

units}}$.

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Solve and will mark brainliest
Sergeu [11.5K]

There is a 60 minute gap between the two clocks.

These 60 minutes result of a 1 min advance in one for each hour and a 2 min loss in the other.

if we are going 2 mins back and 1 min in

We have a 3 min gap/hour

then to reach a 1 hour gap we would need to go for 2+1+2+1+2+1+2....(20 hours)

since each 3 represent an hour,

to get 60 min gap>60/3=20 hours

Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40

or

Take clock 2 for example, which read 11:00, in reality the time is (11:00+20×2 minutes)=11:40

Now go back 20 hours from that;

11:40-20=00:40-9=15:40

There's ur answer 15:40 :)

7 0
2 years ago
How many terms does the expression q÷2 +g-2k​
Eduardwww [97]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
Plz help i need it bad
lakkis [162]

Answer:

See below

Step-by-step explanation:

Vertices are the black dots of the figure:

Point Q is at (1,4)

Point R is at (3,-2)

Point S is at (0,-1)

Point T is at (-2,2)

5 0
2 years ago
Read 2 more answers
Evaluate 2b^2 − 4a + 4a^2 for a = 3 and b = −8.
kipiarov [429]

(2*(-8)^2)-(4*3)+(4*3^2)

128-12+36

152

6 0
2 years ago
Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
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