Is there a picture or something because how many tiles does he wanna make
Answer:
Step-by-step explanation:
<u>The new dimensions will be:</u>
The area is 540
<u>Using area equation we get:</u>
- (10 + x)(22 + x) = 540
- x² + 32x + 220 = 540
- x² + 32x = 320
- x² + 2x*16 + 256 = 320 + 256
- (x + 16)² = 576
- x + 16 = √576 (Ignoring the negative root as the length is never negative)
- x + 16 = 24
- x = 8
<u>The new dimensions are:</u>
- 10 + 8 = 18 ft and
- 22 + 8 = 30 ft
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer:30 cm
Step-by-step explanation:
Area is found by two side lengths multiplied together, the two side lengths in the problem are 5cm and 6cm, 5 times 6 is 30, (plus add the measurement) which is 30 cm. :))
Answer:
a. See attachments
B. 163630.2ft
C. 147056.70ft
D. 49205.4ft
Step-by-step explanation:
Check attachments for details
Angle a.. Angle of dep to beginning of runway
Angle b... Angle of del to end of runway
AD... Altitude of plane
DB..... Ground distance before touch down
AC... Air distance travelled until touch down on the near end of runway
