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3 years ago

Identify and calculate the area for each triangle 1-6

Mathematics

1 answer:

Basile [38]3 years ago

3 0

Formula For calculating the area for triangle is base length times height divided by two. In this case, it’ll be ‘a’ x ‘b’ divided by 2.

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THE WORLD'S HARDEST QUESTION<br><br> 9307 * 8754

sp2606 [1]

81473478 is the correct answer
hope this helped

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3 years ago

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Given the following sequence, find the 25th term: 0, 1, 2, 3, 4, . . .

Burka [1]

The answer for this question would be 24 because 0 is included.

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3 years ago

A school made $880 from ticket sales for the school play. From the ticket sales, $250 were from adult tickets.

Alecsey [184]

Answer:

126 Students

Step-by-step explanation:

First, you subtract the money from the adult tickets from the total ($880), that leaves $630.

Since each student ticket is $5, you divide $630 by 5, which equals 126.

So, 126 students attended.

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3 years ago

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Please help me <br><br>If 180°<α<270°, cos⁡ α=−8/17, what is sin -α?

rewona [7]

Starting from the fundamental trigonometric equation, we have

$\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}$

Since $180$ , we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

$\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}$

Plugging the numbers, we have

$\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}$

Now, just recall that

$\sin(-\alpha)=-\sin(\alpha)$

to deduce

$\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}$

6 0

3 years ago

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Please help, i will give brainliest to whos first

Wittaler [7]

Thanks with all of my heart!

ik im not first but have a lovely day! u are really kind! never forget that!

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3 years ago