For (h+g)(x) you just add the two functions:
(h+g)(x) = 4x + 2x^2
For (h•g)(x) you multiply them:
(h•g)(x) = 4x • 2x^2 = 8x^3
For (h-g)(x) you subtract them:
(h-g)(x) = 4x - 2x^2
For (h-g)(-2) you sub -2 into the equation we just created:
(h-g)(-2) = 4(-2) - 2(-2)^2
(h-g)(-2) = -8 - 2(4)
(h-g)(-2) = -8 - 8
(h-g)(-2) = -16
If the circle has the same center as the diagonals of a square and the radius of the circle is smaller than 1/2 the diagonal of the square but larger than 1/2 the length of the side of a square, then there are 8 points of intersection -- 2 at each corner of the square.
If the radius of the circle is smaller than 1/2 the side length of the square and the center is as described above, there are no points of intersection.
If the circle is located outside the square it can have 1 tangent point or 2 intersection points depending on the location conditions of the circle in relation to the square.
D = sqrt((0-18)^2 + (-5--10)^2)
D= sqrt ((-18)^2 + (5)^2)
D= sqrt( 324 + 25)
D= sqrt ( 349)
D = 18.7
9514 1404 393
Answer:
C. graph Y
Step-by-step explanation:
Starting with f(r) = -3r +3, the inverse function can be found from ...
r = f(y)
r = -3y +3
r -3 = -3y
(r -3)/-3 = y
y = -1/3r +1
The inverse function will have a slightly negative slope and a y-intercept of 1. This matches graph Y.
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