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igor_vitrenko [27]
3 years ago
7

Which fractiona are equivalent to 2/12+4/12

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

6/12 or 3/6 or 1/2

Step-by-step explanation:

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I give 20! Find the surface area. And without explanation please, I don’t have enough time.
oee [108]

Answer:

816 cm²

Step-by-step explanation:

Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.

✔️Surface area of the larger rectangular prism:

Area = L*W*H = 20*5*6 = 600 cm²

✔️surface area of the smaller rectangular prism:

Area = L*W*H = 12*4*6 = 288 cm²

✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.

Area = L*W = 12*6 = 72 cm²

Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².

8 0
3 years ago
A stereo store is offering a special price on a complete set ofcomponents (receiver, compact disc player, speakers, cassette dec
Korvikt [17]

Answer:

Step-by-step explanation:

(a)

The number of receivers is 5.

The number of CD players is 4.

The number of speakers is 3.

The number of cassettes is 4.

Select one receiver out of 5 receivers in 5C_1 ways.

Select one CD player out of 4 CD players in 4C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 4 cassettes in 4C_1 ways.

Find the number of ways can one component of each type be selected.

By the multiplication rule, the number of possible ways can one component of each type be selected is,

The number of ways can one component of each type be selected is

=5C_1*4C_1*3C_1*4C_1\\\\=5*4*3*4\\\\=240

Part a

Therefore, the number of possible ways can one component of each type be selected is 240.

(b)

The number of Sony receivers is 1.

The number of Sony CD players is 1.

The number of speakers is 3.

The number of cassettes is 4.

Select one Sony receiver out of 1 Sony receivers in ways.

Select one Sony CD player out of 1 Sony CD players in ways.

Select one speaker out of 3 speakers in ways.

Select one cassette out of 4 cassettes in 4C_1 ways.

Find the number of ways can components be selected if both the receiver and the CD player are to be Sony.

By the multiplication rule, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is,

Number of ways can one components of each type be selected

=1C_1*1C_1*3C_1*4C_1\\\\=1*1*3*4\\\\=12

Therefore, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is 12.

(c)

The number of receivers without Sony is 4.

The number of CD players without Sony is 3.

The number of speakers without Sony is 3.

The number of cassettes without Sony is 3.

Select one receiver out of 4 receivers in 4C_1 ways.

Select one CD player out of 3 CD players in 3C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 3 cassettes in 3C_1 ways.

Find the number of ways can components be selected if none is to be Sony.

By the multiplication rule, the number of ways can components be selected if none is to be Sony is,

=4C_1*3C_1*3C_1*3C_1\\\\=108

[excluding sony from each of the component]

Therefore, the number of ways can components be selected if none is to be Sony is 108.

(d)

The number of ways can a selection be made if at least one Sony component is to be included is,

= Total possible selections -Total possible selections without Sony

= 240-108

= 132  

Therefore, the number of ways can a selection be made if at least one Sony component is to be included is 132.

(e)

If someone flips the switches on the selection in a completely random fashion, the probability that the system selected contains at least one Sony component is,

= \text {Total possible selections with at least one Sony} /\text {Total possible selections}

= 132  / 240

= 0.55

The probability that the system selected contains exactly one Sony component is,

= \text {Total possible selections with exactly one Sony} /\text {Total possible selections}\frac{1C_1*3C_1*3C_1*3C_1+4C_11C_13C_13C_1+4C_13C_13C_13C_1}{240} \\\\=\frac{99}{240} \\\\=0.4125

Therefore, if someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains at least one Sony component is 0.55.

If someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains exactly one Sony component is 0.4125.

6 0
3 years ago
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Misha Larkins [42]

Answer:

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4 0
2 years ago
What's 80/100 times $90
Fofino [41]

Answer:

72

Step-by-step explanation:

Well to make life easier just simplify the fraction

80/100 could be simplified to 4/5

4/5*90 is 72

7 0
3 years ago
Read 2 more answers
A sequence is a function whose domain is the set of __numbers.
MariettaO [177]
Answer - natural

A sequence is a function whose domain is the set of natural numbers.
5 0
3 years ago
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