Answer:
5. x= 13 y= 18.4
6.
Step-by-step explanation:
question 5:
tan45=x/13
multiply both sides by 13 to get x by its self.
end up with 13×tan45 so put that in the calculator to get x
then you do cos45= 13/y
multiply by y on both sides.
end up with y×cos45=13
divide the cos45 by both sides
put 13/cos45 to get y
question 6:
sin30=4/x
multiply x on both sides
end with x×sin30 =4
divide sin30 on both sides
put 4/sin30 in a calculator to get x
same thing again but with tan30 ahaha
(x - a)^2 + (y - b)^2 = (y - d)^2
<span>x^2 - 2ax + a^2 + y^2 - 2by + b^2 = y^2 - 2dy + d^2 </span>
<span>Subtract y^2 from both sides... </span>
<span>x^2 - 2ax + a^2 - 2by + b^2 = -2dy + d^2 </span>
<span>Now I would just substitute in the the values (a = -4, b = 17/8, d = 15/8)... </span>
<span>x^2 - 2(-4)x + (-4)^2 - 2(17/8)y + (17/8)^2 = -2(15/8)y + (15/8)^2 </span>
<span>Simplify... </span>
<span>x^2 + 8x + 16 - (17/4)y + 289/64 = -(15/4)y + 225/64 </span>
<span>Add (17/4)y to both sides... </span>
<span>x^2 + 8x + 16 + 289/64 = (2/4)y + 225/64 </span>
<span>x^2 + 8x + 16 + 289/64 = (1/2)y + 225/64 </span>
<span>Subtract 225/64 from both sides... </span>
<span>x^2 + 8x + 16 + 1 = (1/2)y </span>
<span>x^2 + 8x + 17 = (1/2)y </span>
<span>Multiply both sides by 2... </span>
<span>2x^2 + 16x + 34 = y </span>
<span>...which is equal to equation D.</span>
Answer:
Area of triangle = 15 square units
Step-by-step explanation:
We need to find area of the triangle, given the vertices:
A=(4,0)
B=(1,5)
C=(7,5)
The formula used is: 
We have: 
Putting values and finding area

We will be ignoring negative sign, because area of triangle is positive.
So, Area of triangle = 15
Using properties of logarithms:
log(m+n) = log(m.n)
log(m-n) = log (m/n)
we get,
log(32x16/64)
On simplifying:
log(8)
and 8= 2^3
therefore,
log(2^3)
again using another property for exponents in logarithms we get:
3 log 2 <---- Answer