Answer choices are:
A. Invalidate, because energy should not leave a closed system
B. Invalidate, because the amount of energy should stay constant
C. Validate, because an aquarium is an open system that loses and gains energy
D. Validate, because the amount of energy lost was replaced by matter.
The correct answer choice is:
C. Validate, because an aquarium is an open system that loses and gains energy.
Explanation:
As we know that, the law of conservation of energy is that the total amount of energy of an isolated system prevails to be constant, it is said to be maintained or conserved over time. This law means that energy can neither be created nor be destroyed; rather, it can only be converted or transferred from one form to another.
A cross between two linked genes was done in coupling configuration and in repulsion. In coupling, the recombination frequency is greater than 1/16 and in repulsion, the recombination frequency is less than 1/16
If the cross between two linked genes is in coupling, then the recombination frequency is greater than 1/16 having the genotype aabb and phenotype ab.
If the cross between two linked genes is in repulsion, then the recombination frequency is less than 1/16 having the genotype aabb and phenotype ab.
Coupling is the gamete entered having genes from identical parents having same inheritance.
Repulsion is the gamete entered from different parents having separate inheritance.
Genes in coupling configuration on a homologous chromosome have two wild alleles and two mutant alleles on the other homologous chromosome.
Genes in repulsion configuration have a wild allele on one gene and the second gene on other homologous chromosome having a mutant allele.
Learn more about Homologous chromosome here, brainly.com/question/27258467
#SPJ4
Answer:
Heterozygous dominant (Bb) and homozygous recessive (bb)
Explanation:
This cross involves the gene that codes for color blindness in whales. The allele for no color blindness/normal vision (B) is dominant over the allele for color blindness (b). This means that B will mask the phenotypic expression of b in a heterozygous state (Bb).
According to the question, one of the parents is color blind meaning it possesses the homozygous recessive genotype (bb) while the other parent (pearl) has a normal vision which can either be homozygous dominant or heterozygous dominant since the normal vision allele (B) is dominant.
However, since one of the two offsprings (sons) is also color blind, this implies that the parent with normal vision is heterozygous i.e. contains both dominant and recessive alleles, for the trait. What happens is that, when a bb and Bb parent are crossed, they produce gametes with either a recessive or dominant allele.
The Bb produces gametes with B and b alleles while the bb produces gametes with b and b alleles. When this are crossed using a punnet square, four possible offsprings will be produced with two distinct genotypes: Bb and bb. Hence, this means that there is a 1/2 chance of producing an offspring with the recessive trait from this cross as the case is in the whales.
