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tia_tia [17]
3 years ago
10

R= m/2 (c + K) for k

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

                  \bold{K=\frac{2r}m-c=\frac{2r-cm}m}

Step-by-step explanation:

\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}

Or if you mean r= m/[2(c + K)]

\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}

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Find the 12th term of following geometric sequence 5, 20,80, 320,
vesna_86 [32]
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The perimeter of a rectangle is 141 feet, and the length is twice the width. What are the dimensions of the rectangle?
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3 years ago
Factor Completely: x^2-13x-48
salantis [7]

Answer:

Therefore,the required factors are ( x - 16 ) and ( x + 3 )is

Step-by-step explanation:

Given:

x^{2} -13x-48

To Factorize:

Solution:

First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.

-48 = -16 × 3

Here, -16 and 3 are the two  required numbers

now the given expression we will split the middle term  and Factorize the given equation.

x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)

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4 0
3 years ago
Find the fifth term in the geometric sequence, given the first term and the common ratio. a1=5 and r=-3
Lunna [17]

Answer:

<h2>405</h2>

Step-by-step explanation:

The nth term of a geometric sequence is given by the formula

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3 years ago
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