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tia_tia [17]
3 years ago
10

R= m/2 (c + K) for k

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

                  \bold{K=\frac{2r}m-c=\frac{2r-cm}m}

Step-by-step explanation:

\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}

Or if you mean r= m/[2(c + K)]

\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}

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