Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000
Answer: 0.845
Step-by-step explanation: 1.69 divided by two is 0.845
Answer:
Standard Form: y = 4(x-1)(x+5)
Step-by-step explanation:
4 is the leading coefficient, so it should go in front. When making a standard quadratic equation, you must do the opposite for each of the roots (negative to positive, positive to negative.)
if you’re asking for a general form quadratic equation, then sorry, I am unable to help you with that :(
Answer:
1) 8 2) -33/9
Step-by-step explanation:
1) (1/2)x = -1/2 + 9/2
(1/2)x = 4 x = 8
2) distributing 3/2, 9x/2 - 15/2 = -24
9x/2 = -24 + 15/2
9x/2 = -33/2
9x = -66/2
9x = -33
x = -33/9
P= 2l+2w
P-2l= 2w
1/2P -l= w
Rearrange into standard form.
w= 1/2P -l