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stepladder [879]
3 years ago
12

If you dissolve 50g of sugar in 30g of water (is it possible!) what would be the sugar concentration?

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0
100 percent more of concentraion
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Which methods could you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at (0,0) and
Olenka [21]

Answer:

add the y coordinates of the two lines and divide by 2

Step-by-step explanation:

½[0+(-12)]

½[0-12]

½[-12)

y co-ordinate of the midpoint is -6

7 0
3 years ago
What equations is equivalent to the following equation: x+3=12
Dimas [21]

Answer:

2x+6=24. a. aaaaaaaaaaa

8 0
4 years ago
(3ab+2c)^3 what is the answer
svet-max [94.6K]

Answer:

=27a^3b^3+54a^2b^2c+36abc^2+8c^3

Step-by-step explanation:

(3ab+2c)^3

=(3ab+2c) × (3ab+2c) ×

=(3ab+2c)(9a^2b^2+12abc+4c^2)

=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)

=27a^3b^3+36a^2b^2c+12abc^2+18a^2b^2c+24abc^2+8c^3

=27a^3b^3+54a^2b^2c+36abc^2+8c^3

<em>hope this helps....</em>

5 0
3 years ago
There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

6 0
3 years ago
Solve for E. <br><br>h=E/mg​
nekit [7.7K]

Answer:

hmg = E

Step-by-step explanation:

Step 1: Write equation

h = E/mg

Step 2: Multiply both sides by mg

hmg = E

4 0
3 years ago
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