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3 years ago

Please help I'm trying to figure out 4-15 but i don't know how to.

Mathematics

2 answers:

ivann1987 [24]3 years ago

7 0

I believe it’s 80 I have to redo this like 3 times

Scilla [17]3 years ago

3 0

It equals five thousand(5000).

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All radical expressions that are equivalent to 3 2/5

SCORPION-xisa [38]

Answer:

Step-by-step explanation:

√15 (3√5)^2 3√5^2 3√10

4 0

3 years ago

A high school class consists of 5 seniors, 10 juniors, 13 sophomores, and 4 freshmen. Exactly 4 of the juniors are male, and

lozanna [386]

Answer:

The probability that the pair consists of a female junior and a male sophomore is 0.096

Step-by-step explanation:

No of male juniors=4

No of female juniors=10-4=6

No of female sophomores=5

No of male sophomores=13-5=8

As per question,

Probability that the pair consists of a female junior and

a male sophomore = $\frac{6C1\times8C1}{32C2}$ =0.096

Therefore, the probability that the pair consists of a female junior and a male sophomore is 0.096

7 0

4 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2$

$n = 2401$

The minimum sample size is 2401.

4 0

3 years ago

Write an equation that could represent the function table

ExtremeBDS [4]

Answer:

y = $x^{2}$

Step-by-step explanation:

Squaring a number means multiplying the number by itself. 0*0=0. 1*1=1. 2*2=4, and 3*3=9. This is the pattern shown in the table.

8 0

2 years ago

Read 2 more answers

Please help this is what this app is for helping students with school work/homework

inna [77]

We know it's for helping students so chill but I'll help, the number is 9 million and it's in the millions. You see all you have to do is classify the place value and say what the number is called.

6 0

3 years ago