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Marizza181 [45]
3 years ago
6

Find the terminal point on the unit circle determined by 11pi/6 radiants

Mathematics
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

(\frac{\sqrt{3}}{2},-\frac{1}{2})

Step-by-step explanation:

The unit circle has the parametric equation:

x=\cos \theta

y=\sin \theta

where \theta=\frac{11\pi }{6} in our case is the terminal side of the angle in standard position.

We substitute to get:

x=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}

y=\sin \frac{11\pi }{6}=-\frac{1}{2}

\therefore (\frac{\sqrt{3}}{2},-\frac{1}{2}) is the required point.

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