Question

Find the terminal point on the unit circle determined by 11pi/6 radiants

Answer 1

Answer:

$(\frac{\sqrt{3}}{2},-\frac{1}{2})$

Step-by-step explanation:

The unit circle has the parametric equation:

$x=\cos \theta$

$y=\sin \theta$

where $\theta=\frac{11\pi }{6}$ in our case is the terminal side of the angle in standard position.

We substitute to get:

$x=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}$

$y=\sin \frac{11\pi }{6}=-\frac{1}{2}$

$\therefore (\frac{\sqrt{3}}{2},-\frac{1}{2})$ is the required point.