Answer:
1000
Step-by-step explanation:
lets start by labeling the rectangle. let w = width so length(l) = w+4 (i.e 4 more than the width)
Perimeter of a rectangle= sum of all the sides= l+ w+l+w=2l +2w
now we know that p = 2l + 2w = 100
but we know that l=w+ 4
so
2(w+4) +2w=100
2w +8 +2w = 100
4w+8 =100
4w= 92
w=23
and if we substitute into 2l+2w= 100
we will get l =27.
Answer:
small: 6.25
large: 18.25
Step-by-step explanation:
Set the large boxes as x and the small boxes as y (The weight is the constant).
3x+5y=86
6x+2y=122
Now just solve the systems of equations using either substitution or elimination.
-6x-10y=-172 multiply the whole equation by -2 to eliminate
6x+2y=122, add the equations
-8y=-50
y= 6.25
Plug in y either equation:
3x+5(6.25)=86
3x=86-31.25
3x=54.75
x=18.25
Each small box weighs 6.25 kilograms, each large box weighs 18.25 kilograms, to check plug in the values to the other equation to see if they add up correctly.
Answer:
Step-by-step explanation:
An exponent which is a fraction is simplified using a radical.
5/4 is a 4th root radical with an exponent of 5 on the inside.
Once written inside there will be an exponent of 4 raised to the 5th power. Power to a power rule requires that these are multiplied so the exponent on n will be 20. 16 must also be raised to an exponent of 5. See the solution below.
![\sqrt[4]{(16n^4)^5} \\\sqrt[4]{(16^5 n^{20}} \\\sqrt[4]{(16^5 n^{20}} \\32n^5](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%2816n%5E4%29%5E5%7D%20%5C%5C%5Csqrt%5B4%5D%7B%2816%5E5%20n%5E%7B20%7D%7D%20%5C%5C%5Csqrt%5B4%5D%7B%2816%5E5%20n%5E%7B20%7D%7D%20%5C%5C32n%5E5)
