I believe ( i am not 100% certain) that the theoretical probability would be 1/2 or 300/600 and the experimental probability is 252/600, you may need to simplify that
Answer:
<h2>0.1</h2><h2>
Step-by-step explanation:</h2>
please see attached the annotated solution
Given data
p=20%= 0.2
n=15 companies
let x = 5 the number of companies that outsource to overseas consultants
The binomial probability distribution is given as
P(x=λ)=nCx*P^x*q^n-x
we also know that q=1-p
Call the number : x
(1/3)x + 5 = x-6
=> (1/3)x + 5 - (x-6) = 0
=> (1/3)x + 5 - x + 6 = 0
Group (1/3)x with -x, 5 with 6
=> [(1/3)x - x] + (5+6) = 0
=> (-2/3)x + 11 = 0
=> (-2/3)x = -11
=> x = -11 : (-2/3) = 33/2.
Recheck : 1/3 x 33/2 + 5 = 33/6 + 5 = 63/6 = 21/2
33/2 - 21/2 = 12/2 = 6 (21/2 is 6 less than 33/2, satisfied.)
Answer:
43
Step-by-step explanation:
v+47 is equal to 90 degrees, because it's a right angle
v+47=90
to get 90 in this equation, v must equal 43.
that means v=43
Answer:
The cost per print expressed as a slope is 7.125
Step-by-step explanation:
To calculate the cost per print, let’s envision that we have a graphical representation of cost of posters against the number of posters
We have the cost on the y-axis and the number of posters on the x axis
With the information given in the question, we shall be having two data points
Point 1 = (32,126)
point 2 = (48,240)
Now to find the slope of the line which is cost per print, we make use of both points in the slope equation.
Mathematically, slope m will be
m = y2-y1/x2-x1
Thus, we have;
m = (240-126)/(48-32)
m = 114/16
m = 7.125
The cost per print expressed as a slope is 7.125
