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jekas [21]
3 years ago
7

A family has two cars during one particular week the first car consumed 25 gallons of gas and the second consumed 40 gallons of

gas the two cars drove a combined of 1700 miles and the sim of their fuel efficiencies was 50 miles per gallon what were the fuel efficiencies of each of the cars that week ?
Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

56

Step-by-step explanation:

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PLZ ANSWER ASAP DUE IN A FEW MINS
Len [333]

Answer:

Solution given:

diameter=14cm

radius [r]=14/2=7cm

now

area of semi circle or shaded region: ½πr²=½(3.14*7²)=76.93cm²[approximately]

5 0
3 years ago
Please help me on these two
lesya [120]

Answer:

1. A

2. A

Step-by-step explanation:

Im pretty sure that is correct

4 0
3 years ago
I NEED HELP! ITS DUE TODAY!!
Pepsi [2]

Answer:

Step-by-step explanation:i think uyou should add$26,0000 +3.5%=then get your answer

fro the next problem o think you should do $231.55 - $2,200=then get youur answer, that answer will probably be the extra that deena has to pay

4 0
3 years ago
Read 2 more answers
Given circle E with diameter CD and radius EA. AB is tangent to Eat A.
Tatiana [17]

The triangle ACD is the right angle since it is a triangle in a semicircle. The length of AC from the diagram is 21.9feet

<h3>Application of pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the square of the other two sides

From the given circle, the triangle ACD is right angle since it is a triangle in a semicircle

Given the following

Hypotenuse = 26 feet = CD
Base side = AD = 14ft

Required

Length AC

Use the theorem

26^2 = 14^2 + AC^2

AC^2 =  676 - 196
AC^2 = 480
AC = 21.9feet

Hence the length of AC  is 21.9feet

Learn more on pythagoras theorem here: brainly.com/question/343682

7 0
2 years ago
Twenty nine concrete blocks were sampled and tested for crushing strength in order to estimate the proportion that were sufficie
Vitek1552 [10]

Answer:

<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>

<em>(0.83913 , 1.02293)</em>

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the sample size 'n' = 29 blocks

<em>Estimate proportion </em>

                       p = \frac{x}{n} = \frac{27}{29} = 0.93103

<u><em>Step:-2</em></u>

<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>

(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} }  , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} } )

(0.93103 -1.96 \sqrt{\frac{0.93103(1-0.93103)}{29} }  , 0.93103 + 1.96 \sqrt{\frac{0.93103(1-0.93103)}{29} } )

(0.93103 -  0.0919 , 0.93103 +0.0919)

(0.83913 , 1.02293)

<u><em>Final answer</em></u>:-

<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>

<em>(0.83913 , 1.02293)</em>

4 0
3 years ago
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