Question

Which linear equation includes the points (6,0) and (0, – 4)?

Answer 1

Answer:

y= (2/3)x - 4

Step-by-step explanation:

To answer this you'll want to use the slope intercept form of a line:

y= mx + b

So to solve essentially you just have to find the values for m and b

- m represents the slope of the line

- b is the y-intercept (the point where the line crosses the y-axis)

You can figure that b = -4 because the line will cross the y-axis when x = 0, and you are given the point on the line (0,-4), where x is equal to 0.

Now to find the slope of the line, since you are given two points on the line you will want to use the slope equation:

slope = $\frac{y1-y2}{x1-x2}$

So you can assign each of the two points a number (1 or 2) where its values are equal to (x1, y1) or (x2, y2). It does not matter which point gets which number.

In this example:

We will assign the point (6,0) to be (x1, y1),

and we will assign the point (0, -4) to be (x2, y2)

So we end up with the following:

m= $\frac{0- (-4)}{6-0}$

m=  $\frac{0+4}{6}$

m=  $\frac{4}{6}$

Simplify the fraction:

m = $\frac{2}{3}$

From there you just substitute in for m and b into the slope intercept equation