answer is -1 you can check it on the calculator
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Answer:
1/6
Step-by-step explanation:
There is x candy in total and y students in total.
Group A consists of 0.8y students, and group B consists of 0.2y students.
Group A gets 40% of x, or 0.4x. Each student in group A gets 0.4x/(0.8y) = 0.5x/y candy per person.
Group B gets 60% of x, or 0.6x. Each student in group B gets 0.6x/(0.2y) = 3x/y candy per person.
The ratio of candy each student in group A has to the amount of candy each student in group B has is:
(0.5x/y)/(3x/y) = 0.5/3 = 1/6
Answer:
8
Step-by-step explanation:
12-10=2
10-m=2
m=8
Answer:
(10, 3)
Step-by-step explanation:
Solve by Substitution
2x − 4y = 8 and 7x − 3y = 61
Solve for x in the first equation.
x = 4 + 2y 7x − 3y = 61
Replace all occurrences of x with 4 + 2y in each e quation.
Replace all occurrences of x in 7x − 3y = 61 with 4 + 2y. 7 (4 + 2y) − 3y = 61
x = 4 + 2y
Simplify 7 (4 + 2y) − 3y.
28 + 11y = 61
x = 4 + 2y
Solve for y in the first equation.
Move all terms not containing y to the right side of the equation.
11y = 33
x = 4 + 2y
Divide each term by 11 and simplify.
y = 3
x = 4 + 2y
Replace all occurrences of y with 3 in each equation.
Replace all occurrences of y in x = 4 + 2y with 3. x = 4 + 2 (3)
y = 3
Simplify 4 + 2 (3).
x = 10
y = 3
The solution to the system is the complete set of ordered pairs that are valid solutions.
(10, 3)
The result can be shown in multiple forms.
Point Form:
(10, 3)
Equation Form:
x = 10, y = 3
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right