(y+1)=3(x-1) is the answer to your problem
6+0=6
When you add any number to 0, that number stays the same since you aren’t adding anything to it. So the answer is 6.
(70x10)+(6x1)+(4x1/10)+(2x1/100)+(9x1/1000)
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Answer:
(x + 5)(x + 4)
Step-by-step explanation:
