All categories

3 years ago

Lines s and t are perpendicular if the slope of line s is 5 what is the slope of line t

2 answers:

5 0

The slope of line T is -1/5, because perpendicular lines have opposite reciprocal slopes, meaning the opposite sign (positive or negative) and flipped (whole number becomes a fraction).

oee [108]3 years ago

3 0

The slope of line t is -1/5 :)

You might be interested in

100 x 54 + 77 ÷ 2 = ? (RIGHT ANSWER GETS BRAINLIEST)

Nadusha1986 [10]

Answer:

5438.5

Step-by-step explanation:

To complete this equation, we must use the order of operations also known as PEMDAS.

For the case of this problem, we start by multiplying or dividing numbers before adding or subtracting numbers.

First let's start on the left:

100 x 54 + 77 ÷ 2

5,400 + 77 ÷ 2

5,400 + 38.5

5438.5

I hope this helps! Just remember to always add or subtract number last and start on the left, so that you don't get confused.

6 0

3 years ago

Read 2 more answers

Area of ice rink is 404 sq yes what is perimeter

ololo11 [35]

Ok, since the ice rink is a square (which has equal sides) if you multiply 404 times four because a square has 4 sides which is equal to 1616 the perimiter is 1616 sqf

404*4= 1616 p= 1616sq

6 0

3 years ago

A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.

Vlada [557]

Answer:

a) $y=12000(2)^{\frac{t}{50}}$

b) Approx. 27,569 bacteria

c) About 103 minutes

Step-by-step explanation:

This will follow exponential modelling with form of equation shown below:

$y=Ab^{\frac{t}{n}}$

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

$y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}$

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

$y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76$

The number of bacteria after 1 hour would approximate be 27,569 bacteria

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

$y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103$