The first term is 612.
The common ratio is 1.08 and 
The recursive rule is   
 
<u>Step-by-step explanation:</u>
the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.
<u>The first term :</u>
In geometric sequence, the first term is given as  .
.
⇒ 
Now, the geometric sequence follows as 612, 661, ........
<u>The common ratio (r) :</u>
It is the ratio between two consecutive numbers in the sequence. 
Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence. 
⇒ r = 661 divided by 612
⇒ r = 1.08
<u>To find the recursive rule :</u>
A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........
Here, first term  and other terms are obtained by multiplying by r.
 and other terms are obtained by multiplying by r.
- 
Observe that each term is r times the previous term.
- Hence to get nth term we multiply (n−1)th term by r
.
The recursive rule is of the form  
 
This is called recursive formula for geometric sequence.
We know that r = 1.08 and  = 612.
 = 612.
To find the second term  , use the recursive rule
, use the recursive rule  
 
⇒ 
⇒ 
⇒ 
⇒ 