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2 years ago

Find the value of two numbersif their sum is 12 and their difference is 4

Mathematics

2 answers:

daser333 [38]2 years ago

7 0

The simple version is this

12-4= 8

Sonbull [250]2 years ago

5 0

We can set up a system of equations:

x + y = 12
x - y = 4

Adding these two together:

2x = 16
x = 8

Substituting 8 in the first equation:

8 + y = 12
y = 4

Hope this helps!

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vlada-n [284]

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2 years ago

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2 years ago

What is the area of the parallelogram? 15 cm 21 cm 20 cm

padilas [110]

Answer:

Its either 300 or 315

Step-by-step explanation:

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8 0

2 years ago

Find the value of (-4)(6)(-7) -178 168 178 -168

kakasveta [241]

Answer:

168

Explanation:

Before we begin, remember the following:

+ve * +ve = +ve -ve * -ve = +ve

+ve * -ve = -ve -ve * +ve = +ve

Now, for the given problem we have:

(-4) * (6) * (-7)

Let's take the first two terms:

(-4) * (6)

Based on the above rules, the product will be negative

Therefore,

(-4) * (6) = -24

Now, the expression became:

(-24) * (-7)

Again, based on the above rule, the product here will be positive

Therefore,

(-24) * (-7) = 168

Hope this helps :)

4 0

3 years ago

Read 2 more answers

PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.

strojnjashka [21]

A.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\ = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }$

b.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\ \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\= 3 \frac{\sqrt{ 26 }}{ 2 }$

6 0

3 years ago