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andrew11 [14]
3 years ago
6

Find the value of two numbersif their sum is 12 and their difference is 4

Mathematics
2 answers:
daser333 [38]3 years ago
7 0
The simple version is this


12-4= 8
Sonbull [250]3 years ago
5 0
We can set up a system of equations:

x + y = 12
x - y = 4

Adding these two together:

2x = 16
x = 8

Substituting 8 in the first equation:

8 + y = 12
y = 4

Hope this helps!
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A market sells blueberries for $3 per pint. The first day, the market sold a total of $35 worth of blueberries. The second day,
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Answer:Around 50 pints

Step-by-step explanation:

$35=$40

$47=$50

$57=$60

$40+$50+$60=$150/3=50

6 0
3 years ago
How many solutions does the polynomial equation ( x+8)2( x-1) = 0
Olin [163]

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-8 and 1

Step-by-step explanation:

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3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Can someone go over my work please? thanks!​
LenKa [72]

Answer:

Good job they are all right!

Step-by-step explanation:

4 0
3 years ago
Which of the following is a
Naya [18.7K]

Answer:

C

Step-by-step explanation:

57 is a composite number

6 0
2 years ago
Read 2 more answers
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