Answer:
thx
Step-by-step explanation:
yetehhdydbdihdbdjbduhdhd8hdbidhbfjdhidbbdidhbdhdibdbd
Let
be the set of all students in the <u>c</u>lassroom.
Let
and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given




i. We can split up
into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so

ii. 9 students fails both subjects, so we find

By the inclusion/exclusion principle,

Using the result from part (i), we have

and so the probability of selecting a student from this set is

Answer:
77
Step-by-step explanation:
10%=11
because you divide 110 by 10.
Then i would multiply that by 3, giving you 33
110-33=77
I don’t know what you’re tying to say
A cylinder with the same radius and height as a cone will have 3 times the volume of the cone.
Vcone = (1/3)*π*r^2*h
Vcylinder = π*r^2*h