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3 years ago

Name a capital letter that appears to have parallel lines

Mathematics

2 answers:

Ierofanga [76]3 years ago

8 0

H is the answer........

photoshop1234 [79]3 years ago

3 0

H is the answer to this question because the lines are parallel

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Solve each equation.Show your work.<br>Can someone help me please??

Inga [223]

Answer:

1/2a = -5

a = (-5 x 2) : 1

a = -10

8 - b = 9,5

b = 8 - 9,5

b = -1,25

0,1 = -10c

c = 0,1 : -10

c = -0,01

I hope it's helpful.

3 0

3 years ago

4) Use the distance formula to find the length of segment BC.

gogolik [260]

Answer:

Step-by-step explanation:

d= √(5-1)^2+(1-4)^2

d= √4^2+(-3)^2

d= √16+9

d=√25

d=5

8 0

3 years ago

What is the slope of a line that passes through the points (–3, 2) and (–6, 5)?

lilavasa [31]

Answer:

-1

Step-by-step explanation:

just do y2-y1 over x2-x1.

8 0

2 years ago

Jon earns $77 per week. Choose the expression below to help him find out how much he'll earn after x weeks.

Damm [24]

Answer:The equation is $77 x ? =x

8 0

3 years ago

Read 2 more answers

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago