There are 2 x intercepts, x=-4 and x=-1
Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
Answer: The Answer is D, 336 Meters squared.
Step-by-step explanation:
When you increase the dimensions of a right triangle by a scale factor of 4, you increase the area by a factor of 4 squared or 16.
Answer:
m<RPQ = 22°
Step-by-step explanation:
Given:
m<SRQ = 90°
PS = PQ
m<SQR = 46°
Required:
m<RPQ
Solution:
m<SQR + m<SRQ + m<RSQ = 180°
Substitute
46° + 90° + m<RSQ = 180°
m<RSQ = 180° - 136°
m<RSQ = 44°
Find m<PSQ:
m<PSQ = 180° - m<RSQ (Angles on a straight line
m<PSQ = 180° - 44° (Substitution)
m<PSQ = 136°
Find m<RPQ:
∆QSP is an isosceles triangle with two equal base angles. Therefore:
m<RPQ = ½(180° - 136°)
m<RPQ = 22°
I believe is A :)
You are welcome
