3 years ago

Solve the systems of equations using elimination

1 answer:

5 0

Answer:

I can't show you BC I need paper to show u sorry

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disa [49]

( 9 + 5i)( 9 + 8i)
= 9(9+8i)+5i(9+8i)
= 81+72i+45i+40i^2
= 81+117i+40(-1)
= 81-40+117i
= 41+117i. Answer

8 0

4 years ago

BARSIC [14]

Make all a and constant number in different side
10-7=16z-7z+2z
3=11z
z=3/11

7 0

3 years ago

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

3 years ago

pashok25 [27]

The scale factor of 4 was applied to the first triangle. 6 was divided by 4 to get 1.5

5 0

3 years ago

LenKa [72]

-3-(-3)(-1)= 0, so 0 is the solution

5 0

3 years ago