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2 years ago

What is the value of x? help PLS

Mathematics

1 answer:

Juliette [100K]2 years ago

8 0

The value of X is 80 degree.

Please see the attached picture for full solution

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100 POINTS

finlep [7]

Answer:

The graph shows 2 outliers. The scatter plot consist on a straight pattern. As seen, only 2 points are not within the straight line. We can conclude that only two points are outliers. =

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2 years ago

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Which of the following equations best represents the regression line for the data given in the

True [87]

The regression equation for the data given is y= -8.57 -2.31x

Step-by-step explanation:

The first step is to form a table as shown below;

x y xy x² y²

1 4 4 1 16

2 1 2 4 1

3 5 15 9 25

4 10 40 16 100

5 16 80 25 256

6 19 114 36 361

7 15 105 49 225

28 60 360 140 984 ------sum

A linear regression equation is in the form of y=A+Bx

where ;

x=independent variable

y=dependent variable

n=sample size/number of data points

A and B are constants that describe the y-intercept and the slope of the line

Calculating the constants;

A=(∑y)(∑x²) - (∑x)(∑xy) / n(∑x²) - (∑x)²

A=(60)(140) - (28)(360) / 7(140)-(28)²

A=8400 - 10080 /980-784

A= -1680/196

A= - 8.57

B= n(∑xy) - (∑x) (∑y) / n(∑x²) - (∑x)²

B= 7(360)-(28)(60) / 7(60) - (28)²

B=2520 - 1680 /420-784

B=840/-364

B= -2.31

y=A+Bx

y= -8.57 -2.31x

Learn More

Regression equation :brainly.com/question/12280902

Keywords : equations, regression line, data

#LearnwithBrainly

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3 years ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

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3 years ago

Match the expressions given in words with their values when m=6

Assoli18 [71]

Yes i am omg wow hey

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2 years ago

The distance between City A and City B is 250 miles. A length of 2.1 feet represents this distance on a certain wall map. City C

tigry1 [53]

Answer:

650 miles

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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2 years ago

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