Question

Am I correct? (Perfect Square Form)

Answer 1

Answer:

$(x -3 )^2 = 10$

Step-by-step explanation:

Given

$x^2 - 6x - 1 = 0$

Required: Express as a perfect square

$x^2 - 6x - 1 = 0$

Add 10 to both sides

$x^2 - 6x - 1 +10= 0+10$

$x^2 - 6x +9= 10$

Expand

$x^2 - 3x - 3x+9= 10$

Factorize:

$x(x - 3) - 3(x - 3)= 10$

Factorize:

$(x -3 )(x - 3) = 10$

$(x -3 )^2 = 10$