Answer:
11x+y = -28
Step-by-step explanation:
We have two points so we can find the slope
m = (y2-y2)/(x2-x1)
= (-6-5)/ (-2--3)
= -11(-2+3)
= -11/1
The slope is -11
We can use point slope to make an equation
y-y1 = m (x-x1)
y-5 = -11(x--3)
y -5 = -11(x+3)
Distribute
y-5 = -11x-33
Add 5 to each side
y-5+5 = -11x-33+5
y = -11x-28
Add 11x to each side
11x+y = -11x+11x-28
11x+y = -28
This is the standard form of a line
If m(slope)=3, you can start to set up the equation as y=3x+b.
Using y=3x+8, you can plug in the given point being (8,5).
y=5
x=8
5=(3*8)+b
5=24+b
b=-19
The equation would be y=3x-19
An equilateral triangle has 3 congruent sides so the 2 expressions above are equal
3x - 9= 23 - 5x
And then you solve for x
-22=-2x
X=11