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Art [367]
3 years ago
10

What is the area of the kitchen floor in this floor plan?

Mathematics
2 answers:
masha68 [24]3 years ago
6 0
We know that the Area of a Rectangle is:

A = L × W

From the Floor Plan, we know that the Width of the kitchen is 5m. We also know that the Length is 7m. 

Now input what we know into our equation:

A = L ×<span> W
</span>A = 7m ×<span> 5m
</span>A = 35 m^{2}


Hope this helps! 
Aleks [24]3 years ago
4 0

Answer:

Option C

Plato users

Step-by-step explanation:

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a recipe calls for 2 2/3 cups of flour every 1/6 cup of cinnamon.If Richard has 1 cup of cinnamon already in the recipe, how man
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Step-by-step explanation:

2 2/3

=><em>If</em> 8/3 = 1/6

x =1

1/6x = 8/3 ( Divide both sides by <em>1</em><em>/</em><em>6</em><em> </em>)

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1 × 1

<em>The</em><em> </em><em>final</em><em> </em><em>answer</em><em> </em><em>becomes</em><em> </em><em>1</em><em>6</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

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glenn swims 2/3 miles on monday, 3/4mile on wednesday, and 5/6 miles on friday. What is the total of distance glenn swims on tho
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Answer:

She swam a total distance of 2  1/4 miles in those three days.

Step-by-step explanation:

Okay, so- The first thing you need to do is make all denominators equal to make these fractions able to be added together. So, I made all denominators 12. (Tell me if you don't know how to make them all the same denominator, and I'll be happy to help!)

<u>2/3  =  8/12   </u>

<u>3/4  =  9/12 </u>

<u>5/6  =  10/12</u>

Then, I added the numerators together. Like this:

<u>8 + 9 + 10 = 27 </u>

So, this would be:

<u>27/12</u>

Lastly, I changed this improper fraction to a mixed number. I multiplied the denominator twice because it looked like it would be closest to 27 without going over.

<u>12 * 2 = 24 </u>

<em>The "2" will be the whole number in the mixed fraction.</em> Now, I'm going to subtract 24 from the numerator.  

<u>27 - 24 = 3 </u>

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After simplified, the fraction will be:

2 1/4  

<h3>Hope this helps! Let me know if you need help with something else or if you have questions about this problem !</h3>

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