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Sedbober [7]
3 years ago
12

Please help, will give brainliest!

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Answer:

4 & 1

Step-by-step explanation:

(2x+4)(-2x+1)

It's 4 and 1 because those are the points where the graph touches the x axis.

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Given here are a set of sample data: 12.0, 18.3, 29.6, 14.3, and 27.8. the sample standard deviation for this data is equal to _
disa [49]
The answer is 7.9306

Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size

1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
   = 102 / 5
μ = 20.4

2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76

3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
   = 251.58 / 5-1
μ = 62.895 (this is now called sample variance)

4.) Get the square root of the sample variance:
 √62.895 = 7.9306

3 0
3 years ago
Enter your answer in the provided box. what is the emf of a cell consisting of a pb2 / pb half-cell and a pt / h / h2 half-cell
s2008m [1.1K]

The emf of a cell is mathematically given as

E_{cell}  = 0.0532 v

<h3>What is the emf of a cell?</h3>

Generally, the equation for emf  is mathematically given as

Pb/Pb^2^+ //\ H / H_2

where,

Pb is lead

H is hydrogen

Pb^{2+} / Pb has a standard reduction potential of -0.126 volts, while

H_2 / H_2 has a standard reduction potential of 0.0 volts.

E_{cell }= E^0_{cell} - 0.059/n log 1/[Pb^2^+] x [H^+]^2

E_{cell} = 0.126 -  0.059/2 log 1  /  [0.57] x [0.09]^2

E_{cell}  = 0.0532 v

Read more about emf

brainly.com/question/15121836

#SPJ4

6 0
2 years ago
The expression 9/2 = 3 is the same as
sergey [27]
The answer is C 9/2 x 1/3
5 0
3 years ago
If point M was located at (4, -2) and was
Llana [10]

Answer:

The rule to calculate the dilation by a scale factor 1/3 centered at the origin

(x, y) → (3/2x, 3/2y)

Hence, option D is correct.

Step-by-step explanation:

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

  • If the scale factor > 1, the image is enlarged
  • If the scale factor is between 0 and 1, it gets shrunk
  • If the scale factor = 1, the object and the image are congruent

The coordinates of the image can be determined by multiplying the coordinates of the original point by a given scale factor.

Given that the point M was located at (4, -2) and was dilated to M'(6,-3).

It means if we multiply the coordinates of the original point M(4, -2) by 3/2, we get the image point M'(6, -3).

i.e.

M(4, -2) → M'(3/2(4), 3/2(-2)) → M'(6, -3)

In other words, the image M'(6, -3) is obtained after the dilation by a scale factor 3/2 centered at the origin.

Therefore,

The rule to calculate the dilation by a scale factor 1/3 centered at the origin

(x, y) → (3/2x, 3/2y)

Hence, option D is correct.

5 0
3 years ago
PLEASE HELP ME THIS IS MY LAST TRY AND I NEED HELP IF YOU ARE NOT A HUNDRED % SURE PLZ REVEIW
I am Lyosha [343]

First answer is 60.

Second answer is B.

For seven the answer is -7

5 0
3 years ago
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