A triangle in the coordinate plane has coordinates of (3, 5), (1, −3), and (−3, 4). It is translated so that its new coordinates
are (1, 7), (−1, −1), and (−5, 6). What translation occurred? A) It moved left two units and up two units. B) It moved right two units and up two units. C) It moved left two units and down two units. D) It moved right two units and down two units
2 answers:
Given that a triangle in the coordinate plane has coordinates of (3, 5), (1, −3), and (−3, 4). Now these points are translated and the new coordinates are (1, 7), (−1, −1), and (−5, 6).
Questioon says to find which type of translation occured from the given choices.
It can be easily found by drawing the given coordinates.
Original position of the triangle is drawn in Brwon colour.
New position of the triangle is drawn in Green colour.
From graph we can clearly see that each of the original coordinate moves two unit left then 2 units upward to get new coordinate.
Hence choice "A) It moved left two units and up two units." is the final answer.
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Answer:
-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution
Step-by-step explanation:
For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.
Let the original volume of the first alcohol solution be represented with x.
The quantity of the first alcohol solution needed for the mixture is 3% of x
⇒
= 0.03x
Let the original volume of the second alcohol solution be represented with y.
The quantity of the second alcohol solution needed for the mixture is 5% of y
⇒
= 0.05y
The final mixture of alcohol solution is 6% of 100 ml
⇒
= 6 ml
Sum of values of two alcohol solutions = Value of the final mixture
0.03x + 0.05y = 6 ml ..........(1)
Sum of original quantity of each alcohol solution = Original volume of the of mixture
x + y = 100 ml ..........(2)
For easy interpretation, I will be setting up a table to capture all information given in the question.
Component Unit Value Quantity(ml) Value
3% of Alcohol solution 0.03 x 0.03x
8% of Alcohol solution 0.08 y 0.08y
Mixture of 100ml of 6% 0.06 100 6
x + y = 100 0.03x + 0.08y =6
Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.
0.03x + 0.05y = 6 ml ..........(1)
x + y = 100 ml ..........(2)
Using substitution method to solve the simultaneous equation.
Making x the subject of formula from equation (2), we have,
x = 100 - y ..........(3)
Substituting x = 100 - y from equation (3) into equation (1)
0.03(100 - y) + 0.05y = 6
3 - 0.03y + 0.05y = 6
Rearranging the equation,
0.05y - 0.03y = 6 - 3
0.02y = 3
y = 150 ml
Substituting y = 150 ml into equation (3) to get x
x = 100 - 150 ml
x = - 50 ml
The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml
The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml
This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.
Step-by-step explanation:
By pressing the button that looks like this
