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FromTheMoon [43]
2 years ago
12

The sum of eleven and a number is negative nine.

Mathematics
2 answers:
Misha Larkins [42]2 years ago
8 0

Answer:

The sum is 2. ...........

Troyanec [42]2 years ago
4 0

Answer:

11 + x = -9

x = -20

Step-by-step explanation:

"The sum of eleven and a number" can be translated to: 11 + x, where 'x' is the unknown number.

11 + x = -9\\\rule{150}{0.5}\\11 - 11 + x = -9 - 11\\\\\boxed{x = -20}

Hope this helps.

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Y'all I'm in 7th grade and I'm 12 I need help on this exam the question is: A jar contains 5 red marbles, 3 green marbles, and 4
klasskru [66]

Answer:

Im in 7th grade and im in 12 too :) I turn 13 in June 21st

Step-by-step explanation:

The answer is 1/12. 5+3+4=12 So 1/12 propabilty.

P.S. My favorite color is red

If this was helpful, please mark it as brainliest! :D

8 0
3 years ago
Read 2 more answers
Simpifly 6/30 <br> ..... ........
ollegr [7]

Answer:

1/5

Step-by-step explanation:

Divide both numerator and denominator by 6:

1/5

7 0
3 years ago
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(PLEASE HELP)An elevator car in a skyscraper can hold at most 15 people. For safety reasons, each car can carry a
natali 33 [55]

Answer:

70x + 25y + 4x + 4y \leqslant 1500

where x = number of adults

y = number of children

and the extra weights of 4kg of each person.

8 0
3 years ago
In the diagram, triangle GEF and triangle HEF are congruent. What is the value of x?
Harrizon [31]
2(x+2) = 60
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The correct answer is C
8 0
3 years ago
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Suppose that in a random sample of 300 employed Americans, there are 57 individuals who say that they would fire their boss if t
otez555 [7]

Answer:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 300, \pi = \frac{57}{300} = 0.19

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 - 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.1456

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 + 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.2344

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

4 0
3 years ago
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