20% of what number is 80? I need the right answer, this is my last shot of passing.

Analyze the diagram below and complete the instructions that follow.

MAXImum [283]

Answer:

XAW = 3(23) = 69 degrees.

WAY = 23 + 88 = 111 degrees.

ZAY = 8(12) - 23 = 73 degrees.

XAZ = 6(12) + 35 = 107 degrees.

Step-by-step explanation:

8 0

3 years ago

Solve.

baherus [9]

The correct answer is: [C]: " 5 " .
__________________________________________________________
→ " a = 5 " .
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Explanation:
__________________________________________________________

Given: " a + 1 − 2 = 4 " ; Solve for "a" ;

4 + 2 = 6 ;

6 − 1 = 5 ; → a = 5 ;

To check our work:

5 + 1 − 2 = ? 4 ?? ;

5 + 1 = 6 ;

6 − 2 = 4. Yes!

So the answer is: [C]: " 5 ".
_________________________________________________________
→ " a = 5 " .
_________________________________________________________

4 0

4 years ago

You are given two offers for a monthly wage. Option A is to be paid one cent on the first day of the month, with your wages doub

ira [324]

Answer:

Step-by-step explanation:

Option B

Because if you start with one dollar and by day 3 you get 301 dollars and option A only gives you 8 cents on day 3 you get more money by the end of the month if you choose option B.

5 0

3 years ago

Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an

Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean $\mu$ , standard deviation $\sigma$ .

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

8 0

3 years ago

I'm really stuck can someone help?

serious [3.7K]

You got it right the yellow highlighted

7 0

3 years ago