Answer and Step-by-step explanation:
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1. Let's write out the equation to subtract.
7t - 2u - 3v - (t - 3v)
Distribute the negative to the t and -3v.
7t - 2u - 3v - t + 3v (The negatives cancel out)
Now simplify by combining like terms.
6t - 2u
This is the answer because the 3v and -3v cancel out.
2. I don't really understand what this is saying. Is there answer choices for this? But what I think its saying is that the lift has a constant of 2.
3. To find out the amount of terms, we would simplify the equation.
2x + 3y - 5x + yz - x
-4x + 3y + yx
Here, we can see that we have 3 terms in this expression.
-4x is the first term, +3y is the second term, and +yx is the third term.
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#teamtrees #WAP (Water And Plant)
Answer 5.5
Explanation 125 + 125= 250
250 + 50=300
Is 2 125s and 1 50
Each 125 is 2.5
But in this case there is 2 125s
2.5+2.5=5
plus the other half = 5.5
BRAINLIST?
Answer:
194
Step-by-step explanation:
Answer:
Here,
length = 8m
height = 4m
4s = 15 per m^2
Now,
300 per meter = 300 * 15 per m^2
= 4500 per m^2
Answer:
13. 108 inches
14. not similar (sides have different ratios)
15. 68
Step-by-step explanation:
13. You have two relationships between length and width:
2L + 2W = 336 . . . . . the perimeter is 336 inches
L/W = 9/5 . . . . . . . . . .the ratio of length to width is 9/5
Multiplying the second equation by 5/9W, we get
5/9L = W
Now we can substitute that into the first equation to get ...
2L +2(5/9L) = 336
Multiplying by 9 gives us ...
18L +10L = 3024
And dividing by 28 gives ...
3024/28 = L = 108 . . . . inches
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14. Shortest to longest, the ratios of sides are 6 : 8 : 9 and 2 : 4 : 5. There is no value that will multiply the first ratio to give the second ratio. For example, multiplying by 1/3 gives ...
2 : 2 2/3 : 3 . . . . <u>not</u> 2 : 4 : 5
Similar triangles have the same side ratios. These do not, so they are not similar triangles.
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15. MP is a midsegment of triangle JKL and parallel to base JL. A midsegment is half the length of the parallel base. Then JL is twice as long as MP. JL is 68 units long.
