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2 years ago

8

Miles is putting a fence around his garden. The total area of the garden is 4,864 square feet. The length of the garden is 152 f

eet. How many feet of fencing does he need to go around the whole garden?
Help pls!!

1 answer:

JulsSmile [24]2 years ago

3 0

Since the area of any thing is length time width, we can divide 4864 by 152 to get the width of the garden. This gives us 32. Now we need to add 152 + 152 + 32 + 32 to get our total feet of fencing necessary. This would give us 368 feet of fencing.

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andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

<h3><u>Part A</u></h3>

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$\implies ac=2 \cdot -10=-20$

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Rewrite $b$ as the sum of these two numbers:

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Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

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$x=-2, \:\:x=\dfrac{5}{2}$

<h3><u>Part B</u></h3>

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

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The one with arrows are the answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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The equation of a circle has the following format:

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