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zavuch27 [327]
3 years ago
11

For which set of data are the median and mode the same number?

Mathematics
1 answer:
dlinn [17]3 years ago
5 0
1 hghhhhhhgghhghhhhhhhhhhhh
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HELP PLEASE<br><br><br><br> ORDER THE SIDE LENGTHS FROM LEAST TO GREATEST
fgiga [73]

Answer:

HI, IG, GH

Step-by-step explanation:

First, you need to find the missing angle; do this by subtracting 48 and 89 from 180. This means the missing angle is 43. The smallest side will be across from the smallest angle. So in order of least to greatest, the sides are HI, IG, GH.

6 0
2 years ago
What are 64 real square roots
wlad13 [49]
The square roots of 64 are -8 and +8.
4 0
3 years ago
Read 2 more answers
A=10,b=49.5,c=20<br><br><br> answer choices are yes or no
stira [4]

Well, if it is based off the Pythagorean Theorem, here is the formula: a squared plus b squared equals c squared. It also works with c squared minus a squared equals b squared. I hope this helps! Please mark me brainliest!

5 0
3 years ago
Please help I’ll give brainliest if correct
Ira Lisetskai [31]

Answer:

The value of g(22) = 31

Hence, option D is correct.

Step-by-step explanation:

Given

  • f(x)= 4x³ – 10
  • g(x) = 3x - 4 /2

To determine

g(f(2)) = ?

To determine g(f(2)), first, we need to calculate f(2)

so substitute x = 2 in f(x)= 4x³ – 10

f(x)= 4x³ – 10

f(2) = 4(2)³ - 10

f(2) = 32 - 10

f(2) = 22

so

g(f(2)) = g(22)

now substitute x = 22 in g(x) = [3x - 4] / [2]

g(x) = [3x - 4] / [2]

g(22) =  [3(22) - 4] / [2]

g(22) = [66-4] / [2]

g(22) = [62] /  [2]

g(22) = 31

so

g(f(2)) = g(22) = 31

Therefore, the value of g(22) = 31

Hence, option D is correct.

4 0
2 years ago
A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,
zhuklara [117]

Answer:

285.74\text{ inch}^2

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of 3\text{ inch}. The bicycle wheel has a radius of 10\text{ inch}.

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel =10\text{ inch}

area of bicycle wheel =\pi r^2

putting value,

area of bicycle wheel =3.14\times10^2

                                    =314\text{ inch}^2

radius of bicycle training wheel =3\text{ inch}

area of bicycle training wheel =\pi r^2

putting value,

area of bicycle wheel =3.14\times3^2

                                    =28.26\text{ inch}^2

difference in area of bicycle wheel and bicycle training wheel

=\text{area of bicycle wheel}-\text{area of bicycle training wheel}

=314-28.26

=285.74\text{ inch}^2

hence the training wheel is 285.74\text{ inch}^2 smaller than regular wheel

4 0
2 years ago
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