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pickupchik [31]
3 years ago
7

Am I correct ??? I don’t really know

Mathematics
1 answer:
Setler [38]3 years ago
4 0
What you have here is a situation with two <em>similar triangles. </em>The triangle in the lower left is similar to the triangle in the upper right - I've included an image with "cutouts" of those triangles so you can see the similarities. Similar triangles have a very important property: <em>the ratios of their corresponding sides are equivalent</em>. Here, we can set up a ratio between the sides of length 64 and x on the larger triangle, and the corresponding sides of length x and 36 on the smaller triangle. Setting the two equal to each other, we have

\frac{64}{x}= \frac{x}{36}

Multiplying both sides of the equation by 36 and x, we get

64\cdot36=x^2

finally, we take the square root of both sides of the equation to find x:

\sqrt{64\cdot36}=x\\&#10;\sqrt{64}\sqrt{36}=x\\&#10;8\cdot6=x\\&#10;48=x

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Download pdf
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>
4de97e6d942fe2c9047a396b82fccba0.png
0b940014a3beda8e854506c0084127b3.png
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