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3 years ago

For the following system, use the second equation to make a substitution for x in the first equation.

Mathematics

2 answers:

LenaWriter [7]3 years ago

5 0

Answer:

Replace x with 0 and simplify.x,x+5y- 10=0, x = 2 y − 8

Step-by-step explanation:

Gennadij [26K]3 years ago

3 0

Answer:

The resulting equation is $2y-8 + 5y - 10 = 0$

Step-by-step explanation:

For the following system, use the second equation to make a substitution for x in the first equation.

$x + 5y - 10 = 0$ first equation

$x = 2y - 8$ second equation

Now substitute the second equation in first equation

Replace x with 2y-8 in first equation

$x + 5y - 10 = 0$

$2y-8 + 5y - 10 = 0$

The resulting equation is $2y-8 + 5y - 10 = 0$

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A bag with quarters and nickels contains 87 coins.The total amount is $7.35. How many quarter and nickels are in the bag

Nikitich [7]

Answer: 72 nickels and 15 quarters

Step-by-step explanation:

72 times .05 = 3.6 or $3.60

15 times .25 = $3.75

Total = $7.35

.05 is representing the nickels and .25 is representing the quarters and if you take a calculator and do 87-72 you get 15 and you can set it up yourself to double check. But I wouldn't recommend doing it with pennies that's how I got confused so many times and you can also give yourself a similar problem if you want to make sure you know how to do it. Sorry if this was confusing.

8 0

4 years ago

If you apply the changes below to the absolute value parent function, F(x)=|x|, what is the equation of the new function? Shift

UNO [17]

Answer:

y= lx+8l -3 is the answer.

Step-by-step explanation:

f(x) = lxl is absolute function if function is shifted by left of right then its change in x and if function is changed in up or down then its change in y

so f(x) = lx-hl +k is transformation of f(x) = lxl where h is shifting by right side and k is shifting to upward direction.

here its 8 unit left and 3 unit down that is h =-8 and k =-3

so new equation will be

y = lx-(-8)l + (-3)

y = lx+8l -3 is the answer

7 0

3 years ago

the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,

kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

One in ten students are named Joe, hence $p = \frac{1}{10} = 0.1$ .

There are 15 students in the class, hence $n = 15$ .

The probability that at least one of them is named Joe is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

Then:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941$

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0

3 years ago

Steven sold two less boxes of candy for the school fundraiser than Rodney with some of the boxes they sold with 8 how many boxes

wel

If Steven sold two boxes of candy less than Rodney and they sold 8 boxes, you can calculate how many boxes did each sell using the following steps:

Steven ... s = r - 2
Rodney ... r

s + r = 8
r - 2 + r = 8
2 * r = 8 + 2
2 * r = 10 /2
r = 5

s = r - 2 = 5 - 2 = 3

Result: Steven sold 3 boxes of candy and Rodney sold 5 boxes of candy.

7 0

4 years ago

What is the equation of line w<br><br> Write in slope intercept form

makvit [3.9K]

Y=0x + -5 should be the correct answer

8 0

3 years ago