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sweet-ann [11.9K]
3 years ago
12

Problem Page

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

1 machine must be made to minimise the unit cost.

Step-by-step explanation:

<em>Step 1: Identify the function</em>

x is the number of machines

C(x) is the function for unit cost

C (x) = 0.5x^2-150 + 21,035

<em>Step 2: Substitute values in x to find the unit cost</em>

C (x) = 0.5x^2-150 + 21,035

The lowest value of x could be 1

To check the lowest cost, substitute x=1 and x=2 in the equation.

<u>When x=1</u>

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(1)^2-150 + 21,035

C (x) = 20885.5

<u>When x=2</u>

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(2)^2-150 + 21,035

C (x) = 20887

<em>We can see that when the value of x i.e. the number of machines increases, per unit cost increases.</em>

Therefore, 1 machine must be made to minimise the unit cost.

!!

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