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3 years ago

I REALLY NEED HELP ASAP

Mathematics

1 answer:

Nutka1998 [239]3 years ago

4 0

Answer:

3. D 51

4. C 3

5. B 45

6. B 24

7. B {-8,18}

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The graphs of f(x) and g(x) are shown below:

Ivanshal [37]

Answer:

x = -1,5.4

Step-by-step explanation:

We have to solve equation f(x) = g(x) from graph.

In graph f(x) and g(x) will be equal at the point where they meet each other.

Other way to understand this is

since y will be value of f(x) and g(x) .

so we need same value of y for both f(x) and g(x)

and same value for y will be at point where both function meets each other.

now looking at graph ,

we can see that graph of function f(x) and g(x) intersect at two points

(-1,-10) and other is at (5.4,12)

Thus, value of x from pair of solutions (-1,-10) and (5.4,12) is x = -1, 5.4.

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3 years ago

Which algebraic expression represents 10 less than a number

GarryVolchara [31]

Answer:

Step-by-step explanation:

Let the number be x

x - 10

4 0

3 years ago

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How to write seventeen thousand and one hundred six thousandths in standard form

WINSTONCH [101]

Seventeen-thousand and one hundred 6 thousandths written in standard form would be 17,000.106

Hope this helped =)

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3 years ago

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X-5y=2 and 4x+2y=8 using elimination

kobusy [5.1K]

Answer:

y=0 x=2

Step-by-step explanation:

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2 years ago

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For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

3 years ago