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leonid [27]
3 years ago
5

The actual length of a machine is 12.25cm , the measured length 12.2cm find the Absolute error .

Mathematics
1 answer:
NeX [460]3 years ago
6 0

Answer:

Absolute error is 0.05 cm.

Step-by-step explanation:

Given:

Actual length = 12.25 cm

Measured length = 12.2 cm

We need to find Absolute error.

Solution:

Now we can say that;

Absolute error is equal to measured length minus Actual actual.

framing in equation form we get;

Absolute error = |Measured\ length - Actual\ length|= |12.2-12.25| = |-0.05|

Hence Absolute error is 0.05 cm.

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Which values from the set 5,7,11,13 make the inequality w 4 < 8 true
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Find the equation of the line in slope-intercept form (-1,-1) and (1,0)
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Answer:

An equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

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where m is the slope and b is the y-intercept

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Finding the slope between (-1,-1) and (1,0)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)

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substituting m = 1/2 and (-1, -1) in the slope-intercept form of the line equation to determine the y-intercept

y = mx+b

-1=\frac{1}{2}\left(-1\right)+b

-\frac{1}{2}+b=-1

Add 1/2 to both sides

-\frac{1}{2}+b+\frac{1}{2}=-1+\frac{1}{2}

b=-\frac{1}{2}

substituting m = 1/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

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y\:=\frac{1}{2}x-\frac{1}{2}

Therefore, an equation in slope-intercept form of the line will be

  • y\:=\frac{1}{2}x-\frac{1}{2}
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Step-by-step explanation:

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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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