<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
I hope this helps you find the answer you're looking for
Answer:
8x+4
Step-by-step explanation:
4(2x+1)=8x+4
F(x)=a(x-x1)(x-x2)
F(x)=a(x- - 6)(x- -2)
F(x)=a(x+6)(x+2)
-6=a(-3+6)(-3+2)
-6=a(3)(-1)
-6=-3a
2=a
Equation: f(x)=2(x+6)(x+2)
Answer:
3 (equalateral)
Step-by-step explanation: