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tekilochka [14]
3 years ago
12

write the factored form for a quadratic equation with x-intercepts of -6 and -2 and the point (-3,-6) is on the parabola

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0
F(x)=a(x-x1)(x-x2)
F(x)=a(x- - 6)(x- -2)
F(x)=a(x+6)(x+2)
-6=a(-3+6)(-3+2)
-6=a(3)(-1)
-6=-3a
2=a

Equation: f(x)=2(x+6)(x+2)
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Find x, y and ab and how to check if the answer is right ​
iris [78.8K]

Answer:

  x = 2, y = -2, AB = 142

Step-by-step explanation:

The fact that X is the midpoint gives you two relations:

  AX = XB

  AX + XB = AB

Since you have two unknowns, this number of equations is sufficient to find their values. Substituting the given expressions in the above equations, you have ...

  • 8(3x+5) -3(y-7) -22x = 5x +y +23 -4(x-12)
  • 8(3x+5) -3(y-7) -22x + 5x +y +23 -4(x-12) = 2x -5y +128

Simplifying the first of these can make simplifying the second one easier.

  24x +40 -3y +21 -22x = 5x +y +23 -4x +48

  2x -3y +61 = x +y +71 . . . . . . we can use this simplification

  x -4y = 10 . . . . . . . . . . . . . . . . subtract x+y+61

Now, we can simplify the second equation to ...

  2x -3y +61 +x +y +71 = 2x -5y +128

  3x -2y +132 = 2x -5y +128 . . . . . simplify the left side

  x +3y = -4 . . . . . . . . . . . . . . . add -2x+5y-132

Then the two equations we need to solve are ...

  • x -4y = 10
  • x +3y = -4

Subtracting the second from the first, we get

  -7y = 14

  y = -2

Substituting into the first of these simplified equations, we get

  x -4(-2) = 10 . . . . substitute for y

  x +8 = 10 . . . . . . .evaluate

  x = 2 . . . . . . . . . .subtract 8

So, the solution is (x, y) = (2, -2).

Now, the values of AX and XB are ...

  AX = 2x -3y +61 = 2·2 -3(-2) +61 = 71

  XB = x+y+71 = 2 +(-2) +71 = 71 . . . . . . . . matches AX, a good sign

  AB = 2x -5y +128 = 2·2 -5(-2) +128 = 142 . . . . = AX+XB, another good sign

The desired values are x = 2, y = -2, AB = 142.

_____

You check the answer by filling the values into the expressions given in the problem statement and seeing if you get consistent results. Here, we used the simplified expressions, rather than the original expressions, so if we did the simplification wrong, we may have the wrong answer. It is always best to use the original equations. (A machine solver working with the original equations confirms our result, so "confidence is high.")

4 0
3 years ago
If WXY is equilateral and WZY is<br> isosceles, find each missing measure.
timurjin [86]

Answer:

m∠1 = 60°

m∠2 = m∠4 = 39°

m∠3 = m∠5 = 21°

Step-by-step explanation:

ΔWXY is a equilateral angle,

Therefore, all angles of the the triangle are equal in measure.

m∠W + m∠X + m∠Y = 180°

3m∠W = 180°

m∠W = 60°

Since, ΔWZY is an isosceles triangle,

m∠3 = m∠5

m∠3 + m∠Z + m∠5 = 180°

m∠3 + 138° + m∠3 = 180°

2m∠3 = 180 - 138

m∠3 = 21°

Therefore, m∠3 = m∠5 = 21°

Since, m∠2 + m∠3 = 60°

m∠2 = 60 - 21

        = 39°

Since, m∠4 + m∠5 = 60°

m∠4 = 60 - 21

        = 39°

m∠1 = 60°

7 0
2 years ago
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