write the factored form for a quadratic equation with x-intercepts of -6 and -2 and the point (-3,-6) is on the parabola

1 answer:

6 0

F(x)=a(x-x1)(x-x2)
F(x)=a(x- - 6)(x- -2)
F(x)=a(x+6)(x+2)
-6=a(-3+6)(-3+2)
-6=a(3)(-1)
-6=-3a
2=a

Equation: f(x)=2(x+6)(x+2)

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