9514 1404 393
Answer:
Step-by-step explanation:
The cost of each plan (y) is the sum of the initial fee and the product of the mileage charge and the number of miles (x).
First Plan: y = 40 +0.13x
Second Plan: y = 53 +0.08x
__
We can find when the costs are the same by solving this system of equations. A way to do that is to subtract the second equation from the first:
(y) -(y) = (40 +0.13x) -(53 +0.08x)
0 = -13 +0.05x
Multiplying by 20 gives ...
0 = -260 +x
Adding 260, we have ...
x = 260
The plans cost the same for 260 miles of driving.
__
The cost of the plans for that distance is ...
y = 40 +0.13x = 40 +0.13(260) = 40 +33.80
y = 73.80
The cost when the two plans cost the same is $73.80.
This problem can be seen as a rectangle triangle where the vertices are:
Vertice 1: home plate
Vertice 2: First base
Vertice 3: second base.
Right angle between vertice 1 and 2 and vertice 2 and 3.
Distance between each base in 90 '.
Calculating then the distance between home plate and second base we have:
d = root ((90) ^ 2 + (90) ^ 2)
d = 127.28 feets
answer:
the distance between home plate and second base is 127.28 feets
Answer:
I believe the answer is 540* because
Step-by-step explanation:
we start with the fractions, we have 3/4 and 1/4 which makes a whole, to make it easier i added that to 329 to get 330. Then i added 330 to 210 to get 540.
Answer:
its rational
Step-by-step explanation:
:)
