Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?
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The question is incomplete, here is the complete question:
Sulfuric acid is essential to dozens of important industries from steel making to plastics and pharmaceuticals. More sulfuric acid is made than any other industrial chemical, and world production exceeds 2.0×10¹¹ kg per year.
The first step in the synthesis of sulfuric acid is usually burning solid sulfur to make sulfur dioxide gas. Suppose an engineer studying this reaction introduces 1.8 kg of solid sulfur and 10.0 atm of oxygen gas at 650°C into an evacuated 50.0 L tank. The engineer believes Kp = 0.099 for the reaction at this temperature.
Calculate the mass of solid sulfur he expects to be consumed when the reaction reaches equilibrium. Round your answer to 2 significant digits.
<u>Answer:</u> The mass of solid sulfur that will be consumed is 19. grams
<u>Explanation:</u>
The chemical equation for the formation of sulfur dioxide gas follows:
<u>Initial:</u> 10.0
<u>At eqllm:</u> 10-x x
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Partial pressure of sulfur dioxide = x = 0.901 atm
To calculate the number of moles, we use the equation given by ideal gas which follows:
where,
P = pressure of the sulfur dioxide gas = 0.901 atm
V = Volume of the gas = 50.0 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of sulfur dioxide gas = ?
Putting values in above equation, we get:
By stoichiometry of the reaction:
1 mole of sulfur dioxide gas is produced from 1 mole of sulfur
So, 0.594 moles of sulfur dioxide gas will be produced from = of sulfur
- To calculate the number of moles, we use the equation:
Moles of sulfur = 0.594 moles
Molar mass of sulfur = 32 g/mol
Putting values in above equation, we get:
Hence, the mass of solid sulfur that will be consumed is 19. grams