1.
12 liters of 26% acid solution contain

liters of acid.
x liters of 40% acid solution contain

liters of acid.
The third solution is made from the two mixed solution so its volume is

, and the volume of acid in it is

. Its concentration is 33% or 0.33.
The concentration of a solution is the volume of the solution divide by the volume of acid in it.

The answer is B.
2.
12 liters of 16% acid solution contain

liters of acid.
x liters of 40% acid solution contain

liters of acid.
The volume of the third solution is

, and the volume of acid in it is

. Its concentration is 32% or 0.32.

The answer is B.
3.
16 liters of 18% acidsolution contain

liters of acid.
x liters of 27% acid solution contain

liters of acid.
The volume of the third solution is

, and the volume of acid in it is

. Its concentration is 21% or 0.21.

The answer is A.
The answer is x=1 and x=-7
x^2+6x=7
x^2+6x-7=0
(x+7)(x-1)
x=-7 x=1
Answer:
I don't know I'm sorry.............
Answer:
14v-21x-7
Step-by-step explanation:
Answer:
<em>Solve for b. by simplifying both sides of the inequality, then isolating the variable.</em>
Inequality Form:

Interval Notation:
(
−
∞
,
)
Hope this helps :)
<em>-ilovejiminssi♡</em>