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nikklg [1K]
3 years ago
5

To write a polynomial as a product is to _ _ _ _ _ _ it.

Mathematics
2 answers:
Lerok [7]3 years ago
5 0

Answer:

factor

Step-by-step explanation:

i had this on my test and got it right

Alborosie3 years ago
3 0

Answer:

factor is the answer

Step-by-step explanation:

I took the test

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There is a bag of tiles where 8 are red, 5 are blue, 4 are orange, and 3 are green. If one is picked at random, replaced, and an
sesenic [268]

Answer:

i think it is 1/100

Step-by-step explanation:

4/20^2 add all the marbles number together than put the amount of orange marbles on top of it so it is 4/20 than square it

8 0
2 years ago
Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x
alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0
3 years ago
Please help with questions<br> 1d) and 1e)<br><br> Any help is much appreciated thanks
Anestetic [448]

Answer:

1d 6.742     1e 6

Step-by-step explanation: By sketching out the graph you can see the positive x intercept to find 1d

You can also replace h with 25 and isolate t to find 1e

5 0
2 years ago
What is -2x - 10 = - 14x - 7?
jek_recluse [69]

x=4 because if you add 7 to 10 you get -2x-3=-14x then you add -2x to -14x and you get -3=-12 then you divide by -3 and -12 to get 4


3 0
3 years ago
Read 2 more answers
30 random samples of high school students were asked if they played a sport for their high school. Each sample was 20 students.
Ludmilka [50]

Answer:

<em>a. This option is correct</em>

<em>b. This will be true only if we take the </em><em>mode</em><em> as the best representative value </em>

c. <em>This is a correct choice</em>

<em>d. This is not a correct choice</em>

Step-by-step explanation:

<u>Statistics</u>

We are given a dot plot representing 30 random sample proportions of high school students about their sports activities. Based on the data extracted from the plot, we can make some basic conclusions and, less accurately, some predictions.

From the data plot we can see that the following proportions were obtained, along with their absolute frequencies:

0.05 -> 3

0.10 -> 8

0.15 -> 7

0.20 -> 5

0.25 -> 4

0.30 -> 2

Let's select which of the following options are correct

a. A sample proportion of 0.20 means that 4 of 20 high school students responded that they play a sport.

The ratio between the sport playing students to the total of high school students is

\displaystyle \frac{4}{20}=\frac{1}{5}=0.20

Thus, this statement is correct.

b. The best prediction for the proportion of all high school students that play a sport is 0.10.

This will be true only if we take the mode as the best representative value for the whole dataset. Personally, I don't like to trust the mode as a good central tendency result, I'd prefer the mean instead.

c. The mean of the 30 sample proportions calculated to the nearest hundredth is 0.16

Computing the mean of the sample proportions

\displaystyle \bar x=\frac{\sum x_i.f_i}{\sum f_i}

\displaystyle \bar x=\frac{0.00\cdot 1+0.05\cdot 3+0.10\cdot 8+0.15\cdot 7+0.20\cdot 5+0.25\cdot 4+0.30\cdot 2}{1+3+8+7+5+4+2}

\bar x\approx 0.16

<em>This is a correct choice</em>

d. The shape of the sample distribution is fairly symmetrical

We can see the distribution if left-skewed because its peak value is not at the mean value. The mode and the mean are fairly different, thus this choice is not correct

5 0
3 years ago
Read 2 more answers
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