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Mathematics

1 answer:

Tamiku [17]3 years ago

5 0

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A circle has a sector with area \dfrac{1}{2}\pi 2 1 πstart fraction, 1, divided by, 2, end fraction, pi and central angle of \

balu736 [363]

Answer:

Area of circle = 9π

Step-by-step explanation:

Area of sector = $\frac{1}{2} \pi$

Its central angle = $\frac{1}{9}\pi \text{ radians}$

$\text{Area of sector} = \dfrac{\text{Central angle}}{2\pi} \times\text{Area of circle}$

$\text{Area of circle} = \text{Area of sector}\times\dfrac{2\pi}{\text{Central angle}}$

$A = \dfrac{1}{2}\pi\times\dfrac{2\pi}{\frac{1}{9}\pi} = 9\pi$

8 0

3 years ago

40=3x+x^2 How do I find the answer to this

tamaranim1 [39]

Answer:

x = -8, x = 5

Step-by-step explanation:

This can be solved using Factorization method:

$40 = 3x + {x}^{2} \\ \\ \implies \: {x}^{2} + 3x - 40 = 0 \\ \\ \implies \: {x}^{2} + 8x - 5x- 40 = 0 \\ \\ \implies \: x({x} + 8) - 5(x + 8) = 0 \\ \\ \implies \: ({x} + 8) (x - 5) = 0 \\ \\ \implies \: ({x} + 8) = 0 \: \: or \: \: (x - 5) = 0 \\ \\ \implies \: x = - 8 \: \: or \: \: x = 5 \\ \\ x = - 8, \: \: 5$