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2 years ago

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Tamiku [17]2 years ago

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Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave

natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\$

So,

$AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units$

The perimeter of triangle will be:

$P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units$

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

#LearnwithBrainly

7 0

2 years ago

If vector u = <-3.5, -1.5> and vector v = <-1.25, 2.25>, which graph shows the resulting vector for 2v − u?

Sedaia [141]

Answer:

D

Step-by-step explanation:

We know that vector addition is scalar addition.

Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>

2v = < -2.5, 4.5>

2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >

2v-u = < 1 , 6 >

This vector is basically i + 6j which is drawn in option D

8 0

3 years ago

Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

4 0

2 years ago

KOUKLADINA HERE IS THE LIST OF BOTS>... I ALSO PUT THEM IN A MESSAGE TO YOU>>>>>>>>>>>>&g

Elodia [21]

Answer:

HUH WHAT DOES THIS MEAN?

Step-by-step explanation:

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2 years ago

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Nancy has a bank account that has a balance of $320 and allows for a maximum of 6 deposits per month. She has decided that each

LenaWriter [7]

Answer: 320,340,360,380,400,420,440

6 0

2 years ago