The answer is in the picture
<span>The end behavior of a polynomial function is the behavior of the graph of f as
x → +∞ or x → -∞ , depending on its leading coefficient.
In the example, the LEADING COEFFICIENT = - 3x</span>⁵
<span>,when x → +∞, ( - 3x⁵ ) → - ∞ . The end behavior, the polynomial approches minus infinity
</span>
S = ut + (1/2)a(t²) Subtract ut from both sides
(1/2)a(t²) = S - ut Multiply both sides by 2
a(t²) = 2s - 2ut Divide both sides by t²
a= 2s/t² - 2u/t
a= (2S - 2ut)/t²
Answer is C) but there should be parentheses around the term (2S-2ut)
Top equation, minus 10 both sides to get
3x-2y=-10
bottom equation, minus 4x both sides
5y-4x=8
-4x+5y=8
now elimiate y's
multiply top equation by 5 and bottom equaiton by 2 and add them together
15x-10y=-50
<u>-8x+10y=16 +</u>
7x+0y=-34
7x=-34
divide both sides by 7
x=-34/7
sub back
3x-2y=-10
3(-34/7)-2y=-10
(-102/7)-2y=-10
add (102/7) to both sides
-2y=-10+(102/7)
-2y=(-70/7)+(102/7)
-2y=32/7
divide both sides by -2, or times both sides by -1/2
y=-32/14
y=-16/7
(x,y)
(-34/7,-16/7)
Answer:
1 minute and 25 seconds per lap or 1.25 minutes.
Step-by-step explanation:
